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Quiz question of the day
#1
Seeing as we have been having fun with these...

At the Start of the Winter Chess Festival. What is the maximum number of norms possible for the event?
"How sad to see, what used to be, a model of decorum and tranquility become like any other sport, a battleground for rival ideologies to slug it out with glee"
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#2
6

But that is incredibly unlikely because it would require .........

(a) One the 7 norm chasers to lose all games against the other norm chasers.
(b) each IM and GM to lose all games against those 6 remaining norm chasers.
Which puts 6 norm chasers on 4/4
© Those 6 remaining norm chasers would then need to score 2.5/5 against the other 5. Not necessarily with 15 drawn games though.
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#3
'Fraid to say it, You are wrong!
"How sad to see, what used to be, a model of decorum and tranquility become like any other sport, a battleground for rival ideologies to slug it out with glee"
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#4
Big Grin
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#5
The answer is 7 Norms. Phils maths was spot on but Fiona can get 2 norms!
"How sad to see, what used to be, a model of decorum and tranquility become like any other sport, a battleground for rival ideologies to slug it out with glee"
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#6
Andy Howie Wrote:Phils maths was spot on!

Big Grin
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#7
Andy Howie Wrote:but Fiona can get 2 norms!

Are you sure Andy?

Fiona is already a WIM - so surely there would not be much point in her getting an extra WIM norm.

So was 6 the correct answer ?

;P
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#8
Can she not get a WGM and a GM norm though? =|
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#9
Andrew,

just looked up paragraph 0.5 of the Fide Handbook.

IM norm requirement is 2450 performance against opponents average rating of at least 2230
WGM norm requirement is 2400 performance against opponents average rating of at least 2180


So if Fiona acheives IM norm she also achieves WGM norm.

Surprisingly that Pat didn't point that out.

Must be the Christmas spirit taking effect.
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#10
The field is a bit short of the 3 GMs needed for a GM norm.
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