thanks Astrokel but I'm still sorta suck

So the equation is 2NaOH + H2SO4 = Na2SO4 + 2H20

So 1 mole of H2So4 reacts with 2NaOH to give 0.38M

So V(l) = C (mol)/N (moles)

= 0.38M/0.1M

= 3.8

I think I got this wrong because it doesn't look right =/

Hey! how did you get 0.38?

n=cv

n stands for amount in moles,

c is concentration in mol dm

^{-3}, or usually denoted by M

v is volume in dm

^{3}check your formula above,

for example, to get the amount of H2SO4 used,

n = (0.19)(20.0/1000)

Stoichiometric ratio works in this way,

1 mole of H2SO4 required 2 moles of NaOH for complete neutralization.

0.5 mole of H2S04 required 1 mole of NaOH for complete neutralization.

5 moles of H2SO4 required 10 moles of NaOH for complete neutralization.

so after you get moles of H2SO4 used, you can simply get the amount of NaOH required by ratio.

With that, you can find the volume required.